Computational explorations of the Thompson group T for the amenability problem of F
| Autor: | Haagerup, S., Haagerup, U., Ramirez-Solano, M. |
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| Rok vydání: | 2017 |
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| Druh dokumentu: | Working Paper |
| Popis: | It is a long standing open problem whether the Thompson group $F$ is an amenable group. In this paper we show that if $A$, $B$, $C$ denote the standard generators of Thompson group $T$ and $D:=C B A^{-1}$ then $$\sqrt2+\sqrt3\,<\,\frac1{\sqrt{12}}||(I+C+C^2)(I+D+D^2+D^3)||\,\le\, 2+\sqrt2.$$ Moreover, the upper bound is attained if the Thompson group $F$ is amenable. Here, the norm of an element in the group ring $\mathbb{C} T$ is computed in $B(\ell^2(T))$ via the regular representation of $T$. Using the "cyclic reduced" numbers $\tau(((C+C^2)(D+D^2+D^3))^n)$, $n\in\mathbb{N}$, and some methods from our previous paper [arXiv:1409.1486] we can obtain precise lower bounds as well as good estimates of the spectral distributions of $\frac1{12}((I+C+C^2)(I+D+D^2+D^3))^*(I+C+C^2)(I+D+D^2+D^3),$ where $\tau$ is the tracial state on the group von Neumann algebra $L(T)$. Our extensive numerical computations suggest that $$\frac1{\sqrt{12}}||(I+C+C^2)(I+D+D^2+D^3)||\approx 3.28,$$ and thus that $F$ might be non-amenable. However, we can in no way rule out that $\frac1{\sqrt{12}}||(I+C+C^2)(I+D+D^2+D^3)||=\, 2+\sqrt2$. Comment: Accepted for publication in the journal Experimental Mathematics. Updated with the referee suggestions |
| Databáze: | arXiv |
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