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Prediction of magnetic state is of vital important tool to students of applied chemistry for solving different kinds of problems related to magnetic behavior and also magnetic moment. In this manuscript I try to present an innovative method for the identification of magnetic behavior of homo and hetero nuclear mono and diatomic molecules or ions having total electrons (01-20) excluding MOT in a very simple and time savings manner. Introduction The conventional method of determination of bond order and magnetic behavior using M.O.T.1,2,3,4,5 is time consuming. Keeping this in mind, earlier a new innovative method10 was introduced for the determination of bond order of mono and diatomic molecules or ions having total electrons (0120) from which we can easily predict the magnetic behavior of different kinds of homo and hetero nuclear mono and diatomic molecules or ions. The present method is the periodical part of the earlier method10, so that student can forecast bond-order including magnetic behavior of mono and diatomic molecules or ions having total electrons (01-20) without M.O.T.. Previously eight innovative methods including twelve new formulae have been introduced on ‘Hybridization’, ‘IUPAC nomenclature of spiro and bicyclo compounds’, ‘Bond Order of oxide based acid radicals’, ‘Bond order of mono and diatomic molecules or ions having total number of (120)e-s’ and ‘spin multiplicity value calculation and prediction of magnetic properties of diatomic hetero nuclear molecules and ions6,7,8,9,10 for the benefit of students. New important findings in case of Magnetic behavior of homo and hetero nuclear mono and diatomic molecules or ions: Before introducing into innovative method for the prediction of magnetic behavior, first of all we shepherd the species (molecules and ions) with respect to their total number of electrons and bond order (Table-1). Table -1 (Magnetic properties of homo and hetero nuclear mono and diatomic molecules or ions) Molecules or ions Total Number of e-s B.O. Magnetism Remarks on BondOrder H2 + 1 0.5 Para magnetic Fractional H2, He2 2+ 2 1 Diamagnetic +ve integer H2 ,He2 + 3 0.5 Para magnetic Fractional He2, 4 0 Diamagnetic +ve integer Li2 ,He2 5 0.5 Para magnetic Fractional Li2, He2 2-, Be2 2+ 6 1 Diamagnetic +ve integer Be2 ,Li2 7 0.5 Para magnetic Fractional Be2,Li2 28 0 Diamagnetic +ve integer Be2 ,B2 + 9 0.5 Para magnetic Fractional B2, Be2 2-, HF 10 1 Para magnetic Exception B2 ,C2 + 11 1.5 Para magnetic Fractional C2,B2 ,N2 2+, CN+ 12 2 Diamagnetic +ve integer C2 ,N2 + 13 2.5 Para magnetic Fractional N2,CO,NO ,C2 2,CN,O2 2+ 14 3 Diamagnetic +ve integer N2 ,NO,O2 + 15 2.5 Para magnetic Fractional NO,O2 16 2 Para magnetic Exception O2 17 1.5 Para magnetic Fractional F2,O2 2-,HCl 18 1 Diamagnetic +ve integer F2 19 0.5 Para magnetic Fractional Ne2 20 0 Diamagnetic +ve integer In most of the cases generally it is observed that the species having fractional bond-order will be paramagnetic in nature and the species having positive integer bond-order (i.e. bond order = 0,1,2,3 etc) will be diamagnetic in nature. But there is some exception focused in two cases during prediction of magnetic behavior of species having total number of electrons 10 and 16 respectively. In both the cases although they have positive integer bond-order values, 1 and 2, but they are paramagnetic in nature instead of diamagnetic. Explanation on Exception behavior: Species having total number of electrons 10 and 16 will be paramagnetic in nature although they have a positive integer bond order value. In this case, first, we have to predict their magnetic behavior from their magnetic moment values by calculating the number of unpaired electrons by the following two formulae based on bond-order. New two formulae for resolving the number of unpaired electrons (n) based on bond-order in case of paramagnetic substances having total number of electrons 10 and 16. When total number of electrons is 10 [The number of unpaired electrons (n) = 2 x bond order] Eg: B2, HF:[10 electrons, B.O. = 1.0; n = 2 x bond order = 2 x 1.0 = 2.0, Magnetic moment μs = √n(n+2) B.M. = √2(2+2)B.M. = √8 B.M. = 2.83B.M.] |
