Semi-invariant subrings
| Autor: | Uriya A. First |
|---|---|
| Rok vydání: | 2013 |
| Předmět: |
Principal ideal ring
Discrete mathematics Ring theory Ring (mathematics) Endomorphism Algebra and Number Theory Mathematics::Commutative Algebra Mathematics::Rings and Algebras Order (ring theory) Mathematics - Rings and Algebras Subring Semiperfect number Combinatorics Rings and Algebras (math.RA) FOS: Mathematics Endomorphism ring Mathematics |
| Zdroj: | Journal of Algebra. 378:103-132 |
| ISSN: | 0021-8693 |
| DOI: | 10.1016/j.jalgebra.2012.12.015 |
| Popis: | We say that a subring $R_0$ of a ring $R$ is semi-invariant if $R_0$ is the ring of invariants in $R$ under some set of ring endomorphisms of some ring containing $R$. We show that $R_0$ is semi-invariant if and only if there is a ring $S\supseteq R$ and a set $X\subseteq S$ such that $R_0=\Cent_R(X):={r\in R \suchthat xr=rx \forall x\in X}$; in particular, centralizers of subsets of $R$ are semi-invariant subrings. We prove various properties of semi-invariant subrings and show how they can be used for various applications including: (1) The center of a semiprimary (resp. right perfect) ring is semiprimary (resp. right perfect). (2) If $M$ is a finitely presented module over a "good" semiperfect ring (e.g. an inverse limit of semiprimary rings), then $(M)$ is semiperfect, hence $M$ has a Krull-Schmidt decomposition. (This generalizes results of Bjork and Rowen). (3) If $\rho$ is a representation of a monoid or a ring over a module with a "good" semiperfect endomorphism ring (in the sense of (2)), then $\rho$ has a Krull-Schmidt decomposition. (4) If $S$ is a "good" commutative semiperfect ring and $R$ is an $S$-algebra that is f.p.\ as an $S$-module, then $R$ is semiperfect. (5) Let $R\subseteq S$ be rings and let $M$ be a right $S$-module. If $(M_R)$ is semiprimary (resp. right perfect), then $(M_S)$ is semiprimary (resp. right perfect). Comment: 31 pages |
| Databáze: | OpenAIRE |
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