| Abstrakt: |
When the cycloheptatriene iridium(iii) pincer complex (PCP)Ir(CO)(H)(Cl) (3) (PCP = 2,7-(CH2PtBu2)2C7H5) is treated with the bases NaH, 1,8-diazabicyclo[5.4.0]undec-7-ene (DBU) and lithium 2,2,6,6-tetramethylpiperidide (LiTMP) under various conditions different products are obtained. At elevated temperatures and with DBU or LiTMP as a base the trans dihydride (PCP′)Ir(CO)(H)2 (PCP′ = 2-(CHPtBu2)-7-(CH2PtBu2)C7H4) (5) is formed where the π-system extends into one of the phosphine bridges. This compound loses H2 to give the square-planar iridium(i) carbonyl complex 7 (PCP′IrCO). The dihydride 5 can also rearrange to the new isomeric iridium(i) carbonyl 6 (PCP″IrCO, PCP″ = 2,7-(CH2PtBu2)2C7H5). Thus the two hydrides have moved into the ligand backbone creating a methylene group in the 3-position of the cycloheptatriene ring. Alternatively, 6 is formed by a rearrangement from 6a which differs from 6 by having the methylene group in the 4-position of the cycloheptatriene ring. The iridium(i) carbonyl 6a in turn is made from 3 by treatment with DBU at room temperature. Interestingly, when compound 3 is heated to reflux in THF the hydrogen bound at the metal carbon is shifted to a carbon atom in the cycloheptatriene ring generating a ring methylene group (3a). From this complex HCl is eliminated upon chromatography forming 6 as the final product. Quantum chemical calculations at various levels of theory illustrate the relative energetic stabilities of all iridium complexes. [ABSTRACT FROM AUTHOR] |
