A SIMPLE PROOF OF IVADY DOUBLE INEQUALITY.

Autor: KOBAYASHI, NAOKI, NISHIZAWA, YUSUKE, OKAZAKI, KENSHIROH
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Zdroj: Journal of Inequalities & Special Functions; 2023, Vol. 14 Issue 1, p16-20, 5p
Abstrakt: Abstract. In this paper, we give a new proof of Iv´ady double inequality: for x > 0, we have √1 − exp − x²/ (1 + x²) 1/2 < tanh x < ³√ 1 − exp − x³/ (1 + x³) 1/2. [ABSTRACT FROM AUTHOR]
Databáze: Complementary Index