Approach to the 4/3 law for turbulent pipe and channel flows examined through a reformulated scale-by-scale energy budget.

Autor: Zimmerman, Spencer J., Antonia, R.A., Djenidi, L., Philip, J., Klewicki, J.C.
Předmět:
Zdroj: Journal of Fluid Mechanics; 1/25/2022, Vol. 931, p1-34, 34p
Abstrakt: Based on the similarity observed in figure 6, one can predict the values of Graph $\hat {A}$ and Graph $\hat {H}$ at Graph $r 1^*=2$ given a relationship between the Reynolds number and the coefficients Graph $C A$ and Graph $C H$. Thus, from (4.10) we can expect Graph $r {L,\delta }/R$ to saturate for Graph $\delta =0.0033$ when Graph $\textit {Re} \tau \gtrsim 2\times 10^7$ in the channel and Graph $\gtrsim 5\times 10^7$ in the pipe (or Graph $R \lambda \gtrsim 1.2\times 10^4$ and Graph $\gtrsim 1.8\times 10^4$). A linear regime that ends at Graph $r 1/R\lesssim 7\times 10^{-6}$ in the channel (or Graph $r 1/R\lesssim 3\times 10^{-6}$ in the pipe) therefore corresponds to Graph $\hat {A}$ being in the Graph $R$ -scaling regime at Graph $r {L,\delta }$ (for Graph $\delta = 0.0033$). The difference between the transfer term Graph $\hat {T}$ and unity (i.e. the 4/3 law) is equal to the sum of the contributions from the other terms, and thus Graph $\hat {V}$, Graph $\hat {A}$, Graph $\hat {H}$ and Graph $\hat {P} I$ must become negligible for Graph $\hat {T}\approx 1$. If (2.11) were instead expressed in terms of Graph $r 2$ and Graph $D {2ii}$, for example, then negative Graph $\tilde {A} {ii}$ would indicate larger downscale energy transfer in Graph $r 1$ and Graph $r 3$ than one would expect based on the transfer along Graph $r 2$. [Extracted from the article]
Databáze: Complementary Index